Question

find the quadratic polynomial whose zeros are -c. 1/3 and -1​

Answer 1

Answer:

$x^{2} -(\frac{1}{3} -1)x + \frac{1}{3} * -1\\\\x^{2} -(\frac{1-3}{3} )x =\frac{-1}{3} \\\\x^{2} -(\frac{-2}{3} )x -\frac{1}{3} \\\\\\x^{2} +\frac{2}{3} x -\frac{1}{3}$

Multiply each term by 3 ,

$3 * x^{2} + 3 * \frac{2}{3} x - 3 * \frac{1}{3} \\3x^{2} +2x -1$