Question

find the quadratic polynomial whose zeros are given below in photo ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Polynomial = k[x² - (α + β)x + αβ]

Here we have α = 3 +√5 and β = 3 - √5

⇒ p(x) = k[x² - (3 + √5 + 3 - √5)x + (3 + √5)(3 - √5)]

⇒ p(x) = k[x² - 6x + 3² - √5²]

⇒ p(x) = k(x² - 6x + 9 - 5)

⇒ p(x) = k(x² - 6x + 4)

Answer : The polynomial is k(x² - 6x + 4) where k is any constant or real number.