Question

find the quadratic polynomial whose zeros are
root 2 , 1/3​

Answer 1

Given: Zeroes are 2 and 1/3​

To find: The quadratic polynomial

Solution:

• Now we have given the zeroes, so let a = 2 and b = 1/3

• Now the sum of zeroes is:

               a + b = 2 + 1/3

                        = 7/3

• And product of zeroes is:

               ab = 2 x 1/3

                    = 2/3

• The quadratic equation is: x² - (a + b)x + ab = 0

• So putting the values in the equation, we get:

               x² - (7/3)x + 2/3 = 0

Answer:

          So the required equation is: x² - (7/3)x + 2/3 = 0

Answer 2

• Step-by-step explanation:
• Given : Sum of zeroes = (∝ + β) = √2
• Product of the zeroes = = 1/3
• Required quadratic polynomial is
• x² – (∝+β)x + ∝β 
• = x² – (√2)x + 1/3
• = x² – √2x + 1/3