Question

Find the quadratic polynomial
whose zeros is 5/2 and the product is 1
​

Answer 1

$\huge\purple {\mathfrak{Bonjour Mate!}}$

Α = -3

β = 4

Now,

\alpha + \beta = \frac{-b}{a}

-3+4 = \frac{-b}{a}

\frac{-b}{a} = 1

Therefore,

b= -1 , a=1

Now,

\alpha * \beta = \frac{c}{a}

-12= \frac{c}{a}

Therefore, c= -12.

We know standard form of a quadratic polynomial = a x^{2} +bx+c

Hence required polynomial= x^{2} -x-12

Answer 2

Step-by-step explanation:

Α = -3

β = 4

Now,

\alpha + \beta = \frac{-b}{a}

-3+4 = \frac{-b}{a}

\frac{-b}{a} = 1

Therefore,

b= -1 , a=1

Now,

\alpha * \beta = \frac{c}{a}

-12= \frac{c}{a}

Therefore, c= -12.

We know standard form of a quadratic polynomial = a x^{2} +bx+c

Hence required polynomial= x^{2} -x-12