find the quadratic polynomial whose zeros is 8 and their product is 12 find the zero of the polynomia
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Answer:
=k(x²-(α+β)x+αβ)
=k(x²-8x+12)
here k=1
=x²-8x+12
=x²-2x-6x+12
=x(x-2)-6(x-2)
=(x-2)(x-6)
⇒x-2=0 or ⇒x-6=0
⇒x=2 or ⇒x=6
Step-by-step explanation:
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