Math, asked by kiki471, 4 months ago

Find the quadratic polynomial with - ¼ , ¼ as sum and product of its zeroes

• solve and give the answer
• don't answer if you don't know​

Answers

Answered by Anonymous
1

Step-by-step explanation:

Using the quadratic equation formula,

Using the quadratic equation formula,x

Using the quadratic equation formula,x 2

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we get

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 −

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 4

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 41

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 41

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 41 =0

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 41 =0Multiply by 4

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 41 =0Multiply by 44x

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 41 =0Multiply by 44x 2

Using the quadratic equation formula,x 2 −(Sum of root)x+(Product of root)=0Substitute the value in the formula, we getx 2 − 4−1 x+ 41 =0Multiply by 44x 2 +x+1=0

Answered by mohdaareeb9154
1

VERIFIED

( image contains full consept )

Taking L.C.M of denominator, we get,

= k( \dfrac{4 {x}^{2} - x - 4 }{4} )=k( 44x 2 −x−4 )

Now, for k = 4, we have ,

\begin{gathered} = 4( \dfrac{4 {x}^{2} - x - 4}{4} ) \\ \\ = 4 {x}^{2} - x - 4\end{gathered}

=4(

44x 2−x−4)=4x 2−x−4

Hence, the required quadratic polynomial according to the given conditions of sum and product of zeroes is \bold{4{x}^{2}-x-4}4x 2 −x−4

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