Question

Find the quadratic polynomial with the given numbers as the sum and product of it's zeroes
(i) -2, 5
(ii) 8, -3
(iii) $\frac{-1}{4}$, $\frac{1}{4}$

Answer 1

Step-by-step explanation:

$p(x) = {x}^{2} - (sum \: of \: zero)x + prdct \: of \: zeros \\ 1. {x}^{2} - ( - 2)x + 5 = {x}^{2} + 2x + 5 \\ 2. {x}^{2} - 8x - 3 \\ 3. {x}^{2} - \frac{1}{4}x + \frac{1}{4} \\ = \frac{4 {x}^{2} - x + 1 }{4}$