Question

Find the quadratic polynomial with zeroes √2, 1/3​

Answer 1

Answer:

given: sum of polynomial= -b/a = -√2

Multiplying numerator and denominator by 3

=--√2×3/3=- 3√2/3

product of polynomial= c/a = 1/3

the standard form of quadratic polynomial is ax²+bx+c

so, a=3 b=-3√2. c=1

3x²-3√2x+x is the required quadratic polynomial