Question

find the quadratic polynomial with zeroes -2 and 1/3
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Answer 1

Step-by-step explanation:

GIVEN :- α = -2 and β = 1/3

formula :- ax²+bx + c =0

solution- ax² + (α+β)x + (αβ)

ax² + ( -2+1/3)x + ( -2*1/3)

ax² + (-6 +1) x + (-2/3)

ax² +(-5)x +(-2/3)

== ax² - 5x -2/3