Question

Find the quadratic polynomial with zeroes
2 and -1/3​

Answer 1

Answer:

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Answer 2

Question :

• Find the quadratic polynomial with zeroes 2 and -1/3.

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Solution :-

• α = 2
• β = -1/3

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→ Sum of the zeroes = α + β = 2 + (-1/3)

= (6-1)/3

= 5/3

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→ Product of the zeroes = αβ = 2(-1/3)

= -2/3

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Polynomial = x² - s(x) + p

• where, s = sum of zeroes
• p = product of zeroes

Polynomial = x² - (5/3)x + (-2/3)

→ x² - (5/3)x - 2/3 = 0

→ (3x² - 5x - 2)/3 = 0 ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ( L.C.M)

→ 3x² - 5x - 2 = 0

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Required polynomial = 3x² - 5x - 2.