Question

find the quadratic polynomial with zeroes 3 and -3
please fast ​

Answer 1

$\sf\huge\underline{Answer:}$

Given zeroes of a polynomial are 3 and -3

sum of zeroes = 3 + (-3) = 0

product of zeroes = 3 × (-3) = -9

Required polynomial :

${k}^{} [ {x}^{2} - ( \alpha + \beta)x + \alpha \beta ]$

${k}^{} [ {x}^{2} - (0)x + ( - 9)]$

${k}[ {x}^{2} - 9 ]$

Here, k might be any number. Let us consider k = 1

The final answer is ${x}^{2} - 9$