Question

find the quadratic polynomial with zeroes -4/5,1/3

Answer 1

Sum of zeroes = -4/5 + 1/3
= (-12+5)/15
= -7/15

Product of zeroez = -4/5 × 1/3
= -4/15

Equation = x^2 - (sum of zeroes)x + product of zeroes
= x^2 - (-7/15)x + (-4/15)
= x^2 + 7/15x - 4/15

Multiply the equation with 15
= 15x^2 +7x -4

Answer 2

Given the Zeros are :- -4/5 and 1/3

• Sum of Zeros :-

$\frac{ - 4}{5} + \frac{1}{3}$

$= \frac{ - 12 + 5}{15}$

$= \frac{ - 7 }{15}$

• Product of Zeros :-

$\frac{ - 4}{5} \times \frac{1}{3}$


$= \frac{ - 4}{15}$

# To form the quadratic equation

x² - ( sum of zeros )x + ( product of Zeros)

=>
${x}^{2} - (\frac{ -7}{15}) x + ( \frac{ - 4}{15} ) = 0$


$\frac{15 {x}^{2} - 7x + 4 }{15} = 0$


15x² - 7x + 4 = 0

The required equation is
15x² - 7x + 4 = 0