Question

Find the quadratic polynomial zeros below.

a(x²+1)−x(a²+1)​

Answer 1

Answer:

ax^2 - (a^2+1)x + a

aX^2 -a^2x - x + a

ax(x-a) -1(x-a)

(x-a)(ax-1)

Putting the factors equal to zero, we get

x-a = 0 & ax-1 =0

x = a & x = 1/a.

Hence, a and 1/a are zeros of the given quadratic polynomial.