Question

find the quadratic polynomials and whose zeroes exceed the zeroes of x²+5x+6 by a number 2.​

Answer 1

Answer:

$x^2+x=0$

Step-by-step explanation:

Roots of given quadratic polynomial:

$x^2+5x+6=0\\\rightarrow x^2+2x+3x+6=0\\\rightarrow x(x+2)+3(x+2)=0 \\\rightarrow (x+2)(x+3)=0 \\\rightarrow x=-2,-3$

Roots of new quadratic polynomial exceed by 2, so

$x=0,-1$

Equation of a quadratic:

$x^2 - (sum \: of \: roots)x + (product \: of \: roots)=0$

So, new quadratic will be

$x^2+x=0$

Answer 2

Answer:

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