Question

find the quadratic polynomials, for the zeroes a,b given in each Case 1/2,3/2​

Answer 1

Answer:

4x² - 8x + 3 is correct answer.

Step-by-step explanation:

Required polynomial is x²-(alpha + beta) + alpha X beta

Answer 2

Answer:

Let: The Quadratic Polynomial $ax^2 + bx + c$

Given: α = 2, β = -1

⇒ Sum of Zeroes (α + β) = 1/2 + 3/2 = 4/2 = 2 = -b/a

⇒ Product of Zeroes (αβ) = (1/2) (3/2) = 3/4 = c/a

∴ a = 4, b = 8, c = 3

Substituting a,b,c values on the Eq 1 ($ax^2 + bx + c$), we get

= $x^2 -(2)x + 3/4$

= $(\frac{4x^2 - 8x +3}{4})$

= $4x^2 - 8x+3$