Question

find the quadratic polynomials whoes zero are 3& 2​

Answer 1

Answer:

x^2 - 5x + 6

Step-by-step explanation:

METHOD 1

Zeroes = 3,2

x= 3. x=2

(x-3)=0 & (x-2) =0

(x-3)(x-2)=0

x^2-3x-2x+6=0

x^2-5x+6=0

METHOD 2

General form= ax^2 + bx +c

Zeroes = 3,2

Sum of zeroes = 5 = -b/a

Product of zeroes = 6 =c/a

So,

ax^2 + bx + c = ax^2 + (-sum of zeroes) + (product of zeroes)

=> ax^2 + (-5/1) + (6/1)

=> x^2 - 5x + 6

PLS MARK IT BRAINLIEST!!!!!