Find the quadric equation whose roots are 1/√3,-1/√3
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a = 1/underoot 3
B = -1/underoot 3
a + B = 1 / underoot 3 - 1 underoot 3
a + B = 0
a × B = 1 / underoot 3 × - 1/ underoot 3
a×B = - 1/3
required quadratic equation is
x^2- (a + B)x+a×B =0
x^2- 0x -1/3 =0
B = -1/underoot 3
a + B = 1 / underoot 3 - 1 underoot 3
a + B = 0
a × B = 1 / underoot 3 × - 1/ underoot 3
a×B = - 1/3
required quadratic equation is
x^2- (a + B)x+a×B =0
x^2- 0x -1/3 =0
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Answer:
Step-by-step explanation:
the quadratic equation is :
x^2 = 1 / 3
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