Question

find the quadric polynomial whose zeros are 2/3 qnd -1/4

Answer 1

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Answer 2

Hi,
Here is the answer to your query:-

Zeros of polynomial = 2/3 and -1/4
Sum of zeros = 2/3 +(-1/4) = 2/3 - 1/4 = 8-3/12
= 5/12
Product of zeros = 2/3 × -1/4
= -2/12=-1/6
$\bold{QUADRATIC}$ $\bold{EQUATION}$-------->
${x}^{2} + sum \: of \: zeros \: \:(x )\: + product \: of \: zeros = 0$
${x}^{2} + \frac{5}{12}x + ( - \frac{1}{6} ) = 0$
${x}^{2} + \frac{5}{12}x - \frac{1}{6} = 0$
$\frac{12 {x}^{2} + 5x - 2 }{12} = 0$
$12 {x}^{2} + 5x - 6 = 0$
Thanks
⭐SHIVAM⭐