Find the quadric polynomials whose zero are route2+ 3 and route 2-3
Answers
Answered by
1
The required polynomial is
x^2 -{(√2+3)+(√2-3)}x+(√2+3)(√2-3)
=x^2-(√2+3+√2-3)x+(√2)^2-(3)^2
=x^2-2√2x+2-9
=x^2-2√2x-7
x^2 -{(√2+3)+(√2-3)}x+(√2+3)(√2-3)
=x^2-(√2+3+√2-3)x+(√2)^2-(3)^2
=x^2-2√2x+2-9
=x^2-2√2x-7
Similar questions