Question

find the quadric polynomical whose zeroes are 4 and -2​

Answer 1

Given:

• Zeroes of the quadratic polynomial are 4 and -2

To find :

• Quadratic polynomial .

Solution :

• As we know that :

Quadratic polynomial = x^2-(sum of zeroes)x+ product of zeroes

=> p(x) = x^2 -(4+(-2))x+(4)(-2)

=> p(x) = x^2 -2x-8

Hence the polynomial is x^2-2x-8

Answer 2

Answer:

x² - 2x - 8 = 0

Step-by-step explanation:

Given that, The zeroes of quadratic polynomial is 4 , - 2 .

As we know that,

Quadratic polynomial = x²- ( sum of zeroes)x + (product of zeroes) = 0

=> P(x) = x² - [( 4 +(-2)]x + (4 × - 2) = 0

=> P(x) = x² - 2x +(-8) = 0

=> P(x) = x² - 2x - 8 = 0

Therefore, the polynomial is x² - 2x - 8 = 0.