Question

find the quadritc if its roots are 3 & -10​

Answer 1

Step-by-step explanation:

hey there your ans in attachment

Answer 2

Answer:

Let

$\alpha = 3 \beta = - 10$

Therefore the required quadratic equations is:-

$x {}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

$x {}^{2} - (3 + ( - 10))x + 3 \times ( - 10) \\ x { }^{2} - ( - 7)x + ( - 30) = 0 \\ x {}^{2} + 7x - 30 = 0$

x2+7x-30=0is the required quadratic equation