Question

find the quadritic polynomial sum of whose zeroes is 8 and their product is 12. hence find the zeroes of polynomial

Answer 1

hi friend,

the polynomial will be

→x²-(sum of zeros)x+product of zeros

→x²-8x+12 is the required polynomial

now, x²-8x+12

→x²-6x-2x+12

→x(x-6)-2(x-6)

→(x-2)(x-6)

so the zeros are 2 and 6


I hope this will help u :)

Answer 2

Hey there !!



Sum of zeroes = 8
Product of zeroes = 12

Quadratic polynomial :-

x²-(sum of zeros)x+product of zeros

x²- 8x+12 -----> Required Polynomial !!

Now , Let us find their zeroes !!

For this we have to split the middle term !

x²- 6x-2x+12 -----> Splitting the middle term

x(x-6)-2(x-6)

= [ x - 2 ] [ x - 6 ]
x = 2 , x = 6

Hence ,
the zeros are 2 and 6