Question

Find the quantity of charge require for the decomposition of 3.6g of water

Answer 1

Answer:

Gram atomic mass of water (H2O) = (1×2+16) gm = (2+16) gm = 18 gm

∴ Number of molecules in 18 gm of water = 1 mol

∴ Number of molecule in 1 gm of water = 1/18 mol

∴ Number of molecule in 3.6 gm of water = (1/18 x 3.6)mol = 0.2 mol

Explanation:

Answer 2

Answer:

2H

2

O(l)+2e

−

→H

2

(g)+2OH

−

(aq)

Thus, the electrolysis of 1 mole of water requires 2 moles of electrons or 2 faraday of charge.

54 g of water corresponds to

18

54

=3 moles which will require 3×2=6 faraday of charge for electrolysis.