Question

Find the quantity of heat required to raise the temperature of 1 kg of water from 10°c to 90°c.



$\huge\mathfrak\red{Solve this }$


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Answer 1

$\huge\underline\mathfrak\red{solution:-}$

Mass of water = 1 kg = 1000g

rise in temperature of water =90-10 =80 °c

specific heat of water = $1 cal g^-1 °C^-1$

Thus, the required heat = mst = 1000×1×80 = 80,000 cal.

✯ _______ ♛ Be BrAiNly ♛_______✯

Answer 2

$\rule{300}{2}$❤

80,000cal is the correct answer.

$\rule{300}{2}$❤