Question

Find the quardic polynomial the sum and product of its zeroes are -3 and 2 respectively ?

Answer 1

given
t+y=3
ty=2
polynomial
${a}^{2} - (t + y)a + ty$
${a}^{2} - ( - 3)a + 2$
(a)2+3a+2

Answer 2

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The quadratic polynomial is...
$\alpha + \beta = - 3 \\ \alpha \beta = 2 \\ then \: \\ x {}^{2} - ( \alpha + \beta )x + \alpha \beta \\ = x {}^{2} - ( - 3)x + 2 \\ = x {}^{2} + 3 x + 2$
I hope it will help you...
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