find the quardict polynomial of the √2,⅓
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Step-by-step explanation:
sum of roots (S.O.R) = √2+1/3
product of roots (P.O.R)= √2(1/3)=√2/3
therefore polynomial is
x^2-(S.O.R)x + (P.O.R)
= x^2 -(3√2+1 )x + √2
3 3
=3x^2 -(3√2+1) + √2
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