Question

Find the quardtic polynomial where sum and product of the zeroes are 9 and 1/9.​

Answer 1

Answer:

9x2-18x+1

Step-by-step explanation:

alpha +beta =9. alpha*beta= 1 / 9. general form of quadratic equation is x 2-(alpha + beta ) X +alpha * beta. x2-9x+1/9. 9x2-18x+1

Answer 2

GiVeN :-

• Sum of zeroes = 9

• Product of Zeroes = 1/9

To FiNd :-

• A quadratic polynomial whose sum and product of zeroes are 9 and 1/9 respectively.

SoLuTiOn :-

We know that for forming a quadratic polynomial we use a formula :-

• => x^2 - (Sum of zeroes) + (Product of zeroes)

$\implies \: {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

Here,

Sum of zeroes = (α+β) = 9

Product of zeroes = αβ =1/9

So,

Quadratic Polynomial is :-

$\implies \: {x}^{2} - (9)x + \frac{1}{9} = 0 \\ \\ \implies \: 9{x}^{2} - 81x + 1 = 0$