Question

Find the qudratic equation whose rooys are AB and BC whose A(0,2),B(0,0),C(4,0)

Answer 1

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Answer 2

given:

AB and BC are roots of quadratic equation

A(0,2) B(0,0) C (4, 0)

B is a origin

AB = √x^2+y^2

AB = √0^2 + 2^2

AB = 2

BC = √ x^2 + y^2

BC = √0^2+ 4^2

BC = 4

roots =2,4

k [x^2 -(2+4)+ (2×4)]=0

k [x^2-6 +8]=0

x^2 -6+8=0 is a quadratic equation

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