Question

Find the quotient (6x 5 +11x 2 +x−3)÷(2x+3)
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Answer 1

Step-by-step explanation:

From the given information, we have the data as follows.

6x ^ 3 - 11x ^ 2 + 7x + 5, 2x - 3

We are asked to divide 6x ^ 3 - 11x ^ 2 + 7x + 5 by 2x - 3

So, we have,

2x - 3) 6x³ - 11x² + 7x + 5 ( 3x² - x + 2 6x³-9x²

- 2x ^ 2 + 7x

- 2x ^ 2 + 3x

4x + 5

4x - 6

+ 11

Therefore, (6x ^ 3 - 11x ^ 2 + 7x + 5) / (2x - 3) = 3x ^ 2 - x + 2 + [11 / (2x - 3)]