Question

Find the quotient and remainder by dividing x square -4x square + 2x + 5 by x-2

Answer 1

Answer:

-3

Step-by-step explanation:

Let $P(x)=x^2-4x^2+2x+5$

$\implies P(x)=-3x^2+2x+5$

and let $Q(x)=x-2$

By using Remainder Theorem on P(x) and Q(x), remainder on dividing P(x) by Q(x) is P(2) -

$P(2)=-3(2^2)+2(2)+5$

$P(2)=-3(4)+4+5$

$P(2)=-12+9$

$P(2)=-3$

Answer 2

Answer:

-3

Step-by-step explanation:

Let P(x)=x^2-4x^2+2x+5P(x)=x

2

−4x

2

+2x+5

\implies P(x)=-3x^2+2x+5⟹P(x)=−3x

2

+2x+5

and let Q(x)=x-2Q(x)=x−2

By using Remainder Theorem on P(x) and Q(x), remainder on dividing P(x) by Q(x) is P(2) -

P(2)=-3(2^2)+2(2)+5P(2)=−3(2

2

)+2(2)+5

P(2)=-3(4)+4+5P(2)=−3(4)+4+5

P(2)=-12+9P(2)=−12+9

P(2)=-3P(2)=−3