Math, asked by rupajharupa6, 8 months ago

find the Quotient and remainder of the
following
4x³ +6x²-23x+18)÷(x+3)

Answers

Answered by sushreesangita10

9

Answer:

Step-by-step explanation:

the zero of 3 is -3

p(x)=4x³+6x²-23x+18

p(-3)=4(-3)³+6(-3)²-23(-3)+18

=4(-27)+6(9)-23(-3)+18

=-108+54+69+18

=-108+141

=33

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