Question

find the quotient and remainder of the question using long division method
(−18z+14z+24z3+18)÷(3z+4) ​

Answer 1

Answer:

$\begin{array}{c} 8 z^{2}-6 z+2 \\ 3 z+4 \sqrt{24 z^{3}+14 z^{2}-18 z+18} \\ 24 z^{3}+32 z^{2} \end{array}</p><p>\begin{array}{l} -18 z^{2}-18 z+18 \\ -18 z^{2}-24 z \end{array}</p><p>\begin{array}{l} 6 z+18 \\ 6 z+8 \end{array} \\ </p><p>Here, \\ </p><p>10 \\ </p><p> and remainder 10$

Answer 2

Answer:

quotient = 24z³+32z²

remainder = 8z²-6z+2