Find the quotient and remairder 4609 division by 251
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Answer:
Here ΔT
b
=373.16K−373.15K=0.01K, K
b
=0.5K/molkg, mass of water(solvent(W
1
))=100g=0.1kg, Molar mass of glucose(M
2
)=180.16g/mol
ΔT
b
=K
b
W
1
n
glucose
n
glucose
=
0.5K/molkg
0.01K×0.1kg
n
glucose
=2×10
−3
=
6.022×10
23
N
a
N
a
=12.046×10
20
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