Question

Find the quotient and the remainder (12x +37x +23) ÷ (4x+3)​

Answer 1

Answer

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Part 1:−

x−1)4x3−3x2+4x−2(4x2+x+54x3−4x2−+_____________________x2+4x x2−x−+_____________________5x−25x−5−+_____________________3Remainder.

Part 2:−

x−2)4x3−3x2+4x−2(4x2+5x+144x3−8x2−+_____________________5x2+4x5x2−10x−+

Answer 2

Answer:

$49x + 23 \div 4x + 3 \\ \\ = 49x \div 4x + 26$