Question

find the quotient and the remainder when 2x^2-7x-15 is divided by x-5​

Answer 1

Answer:

Divide Using Synthetic Division (2x^2+7x-15)÷(x+5)

(2x2+7x−15)÷(x+5)(2x2+7x-15)÷(x+5)

Place the numbers representing the divisor and the dividend into a division-like configuration.

−5-52277−15-15  

The first number in the dividend (2)(2) is put into the first position of the result area (below the horizontal line).

−5-52277−15-15  22

Multiply the newest entry in the result (2)(2) by the divisor (−5)(-5) and place the result of (−10)(-10) under the next term in the dividend (7)(7).

−5-52277−15-15 −10-10 22

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

−5-52277−15-15 −10-10 22−3-3

Multiply the newest entry in the result (−3)(-3) by the divisor (−5)(-5) and place the result of (15)(15) under the next term in the dividend (−15)(-15).

−5-52277−15-15 −10-10