Find the quotient and the remainder when the largest 7- digit is divided by the largest 2-6 number
Answers
Answer:
Did anyone mention the base used for the numerical representations?
Let’s do this in any integer base b≥2.
The largest seven digit number is b7−1.
The largest three digit number is b3−1.
We can do the following algebra (this is polynomial division):
b7–1 = (b4)(b3−1)+b4−1
= (b4)(b3−1)+b(b3−1)+b−1
= (b4+b)(b3−1)+b−1
So when b7−1 is divided by b3−1 the quotient is b4+b and the remainder is b−1.
I will leave it to you to calculate the quotient and remainder with b=10.
Answer:
Let’s do this in any integer base b≥2.
The largest seven digit number is b7−1.
The largest three digit number is b3−1.
We can do the following algebra (this is polynomial division):
b7–1 = (b4)(b3−1)+b4−1
= (b4)(b3−1)+b(b3−1)+b−1
= (b4+b)(b3−1)+b−1
So when b7−1 is divided by b3−1 the quotient is b4+b and the remainder is b−1.
I will leave it to you to calculate the quotient and remainder with b=10.