Question

Find the quotient when the difference of 985 and the number obtained by

interchanging it’s ones and hundreds digits is divided by 33.​

Answer 1

$\rm\dag\large\underline {Given:} \\ 985$

$\rm\dag\large\underline {To \: find:}$

The quotient when the difference of number.

$\rm\dag\large\underline {Solution:}$

We know that ,abc - cba= 99(a-c).

Here,a = 9 ,b = 8 ,C= 5

Therefore, 985 — 589 = 99 (9 — 5)

$\rm\large { \: now \: \frac{985 \: - \: 589}{33} = \: \frac{99 \times 4}{33} = 12 }$

$\rm\bf {thus \: the \: required \: \: quotient \: is \: = \: 12}$

Answer 2

Step-by-step explanation:

We know that ,abc - cba= 99(a-c).

Here,a = 9 ,b = 8 ,C= 5

Therefore, 985 — 589 = 99 (9 — 5)

\rm\large { \: now \: \frac{985 \: - \: 589}{33} = \: \frac{99 \times 4}{33} = 12 }now

33

985−589

=

33

99×4

=12

\rm\bf {thus \: the \: required \: \: quotient \: is \: = \: 12}