Find the quotient: (x2-3x –28) ÷ (x –7)
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0
Answer:
Step-by-step explanation:
Explanation:
First, rewrite the problem as:
x
2
+
3
x
−
28
x
+
7
Next, factor the numerator:
(
x
+
7
)
(
x
−
4
)
x
+
7
Then, cancel the common terms in the numerator and denominator:
(
x
+
7
)
(
x
−
4
)
(
x
+
7
)
x
−
4
However, because you cannot divide by
0
we must qualify this answer:
(
x
2
+
3
x
−
28
)
÷
(
x
+
7
)
=
(
x
−
4
)
where
x
≠
−
7
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