Question

Find the quotients in their exponential form . ​

Answer 1

Answer:

(8/27)^5 * (3/2)^7

(2^3/3^3)^5 * (3/2)^7

2^15/3^15 * 3^7/2^7

2^8/3^8

Answer 2

Step-by-step explanation:

We can write (8/27)^5 as:-

= {(2/3)³}^5

Now, using a law of exponent i.e (a¹)² = (a)^1×2, we can write {(2/3)³}^5 as:-

= (2/3)^3×5

= (2/3)^15

Now, according to the question:-

→ (2/3)^15 ÷ (2/3)^7

Now, using a law of exponent i.e a² ÷ a¹ = (a)^2-1, we can solve (2/3)^15 ÷ (2/3)^7 as:-

= (2/3)^15-7

= (2/3)^8

Therefore, (8/27)^5 ÷ (2/3)^7 will be equal to (2/3)^8