Question

find the quotients without actual division (a3-8)➗+a-2)

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Answer 1

Answer:

$(a^3-8) \div (a-2) =a^2+2a+4$

Step-by-step explanation:

Formula: $a^3 - b^3 = (a -b)(a^2 +ab + b^2)$

$(a^3-8) \div (a-2)\\=[(a)^3 -(2)^3] \div (a-2)\\= [(a-2)(a^2+2a+4)] \div (a-2)\\=a^2+2a+4$