find the quradic polynomial 3 and -3
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Answer:
x²-9=0
Step-by-step explanation:
given,
roots of polynomial = 3 and -3
sum of roots=3+(-3)=3-3=0
product of roots=3x(-3)= -9
quadratic polynomial formed,
x²-(sum of roots)x+(product of roots)=0
=>x²-0x+(-9)=0
=>x²-9=0
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