find the R.I of benzene if angle of c is 42 celicius
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Refractive index of benzene (n) = 1/ sinc
n=1/sin 42°et us take the refractive index of benzene as x
so x= 1/sinc
= 1/0.6691
= 1.51
n=1/sin 42°et us take the refractive index of benzene as x
so x= 1/sinc
= 1/0.6691
= 1.51
JAYANTHNAYAK:
I have asked to find refractive index
sorry bro
et us take the refractive index of benzene as x
so x= 1/sinc
= 1/0.6691
= 1.51
so x= 1/sinc
= 1/0.6691
= 1.51
sin 60 value
plx say me
.8660
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