Find the radius according to given figure
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nitthesh7:
which one.......
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OD=x=OA
radius=r=OD+25
OP=OQ=radius
Δpao is a right Δ
by pytogoras theorem
OA^2+AP^2=OP^2
x^2+45^2=(x+25)^2
x^2+2025=x^2+625+50x
1400=50x
x=28
radius=25+28=53
radius=r=OD+25
OP=OQ=radius
Δpao is a right Δ
by pytogoras theorem
OA^2+AP^2=OP^2
x^2+45^2=(x+25)^2
x^2+2025=x^2+625+50x
1400=50x
x=28
radius=25+28=53
Thanks but there is one mistake it should be op =oq not ap
i ve changed
sorry for the mistake.......my friend
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