Question

find the radius and center of 2x²+2y²-3y=0​

Answer 1

Answer:

Step-by-step explanation:

Dividing the given equation by 2

comparing the given equation with x^2+y^2+2gx+2fy+c=0

we get c=0,g=0,f=-3/2

now,

center = (-g,-f)

          =(0,3/2)

radius=Under root of (f^2+g^2-c)

=3/2

Is the answer correct ,because I have never solved these incomplete equations of circle