Question

find the radius and center of circle whose equation is x²+y²-3x-y+13/2=0​

Answer 1

Answer:

Center = (3/2, 1/2), Radius =3

Step-by-step explanation:

x^2 + y^2 - 3x - y + 13/2 = 0

general form of circle is :-

x^2 + y^2 + 2gx + 2fy + c = 0

So, g = - 3/2 and f = - 1/2 and c =13/2

Center = (-g, - f)

Center = (3/2, 1/2)

Radius = rootg^2 + f^2 - c

Radius = root 9/4 + 1/4 + 14/2

R = root (36/4

R = root 9

R =+- 3