Question

Find the radius and height of a cylinder whose CSA is 110cm² and the circumferencev of the base is 22 cm.​

Answer 1

Let r be the radius and h be the height.

Given:CSA=110cm²

Circumference =22cm

Circumference = 22cm

2πr=22cm

⇒r=22×7/44

⇒r=3.5cm or 7/2 cm

Now,

CSA = 110cm²

⇒2πrh = 110

⇒2×22/7×7/2×h =110

⇒22h=110

⇒h=5cm

Answer 2

Answer:

• r = 3.5 cm
• h = 5 cm

★ GivEn:-

• CSA of the cylinder = 110 cm²
• Circumference of the base of cylinder = 22 cm

★ To Find :-

• The radius
• The height

$\underline{ \huge{ \red{ \sf{Solution:-}}}}$

Let the height and radius of the cylinder be h cm and r cm respectively.

We know, the formula of circumference of base,

$\implies \sf \: 2\pi \: r \: cm$

Therefore, as given in the question,

$\implies \sf \: 2\pi \: r \: = 22$

$\implies \sf \: 2 \times \dfrac{22}{7} \times \: r \: = 22$

$\implies \sf \: r \: = \dfrac{7}{2}$

$\boxed{ \pink{ \sf{ \implies \: \: r = 3.5 \: cm}}}$

Now, the formula of CSA of cylinder is,

$\implies \sf \: 2\pi \: r \:h \: cm^{2}$

Therefore, as given to the question,

$\implies \sf \: 2\pi \: r h = 110$

$\implies \sf \: 2 \times \dfrac{22}{7} \: \times \dfrac{7}{2} \times h = 110$

$\implies \sf \: 22\times h = 110$

$\implies \sf \: h = \dfrac{110}{22}$

$\boxed{ \pink{ \sf{ \implies \: \: h = 5 \: cm}}}$