Find the radius and interval of convergence of sum of ((x - 2)^n)/(3^n) from 1 to infinity.
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the limit exists in R then we say ∑n≥1 an is convergent. ... If x = 1 then the N-th partial sum is N + 1 so the series ∑n≥0 1n diverges .... since the interval [n, n + 1] has length 1.
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|x| as n → ∞. Hence the radius of convergence is 1. For x = 1, the series is a divergent p-series, and for x = −1, the series.
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