find the radius of a circle whose area is equal to half the sum of the areas of the three circles, whose radius are 3 cm, 4 cm, and 5 cm?
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Step-by-step explanation:
Given radius of two circles are 3 cm and 4 cm
Then area of circle whose radius is 4 cm =πr2=π(4)2=16π sq cm
And Then area of circle whose radius is 3 cm =πr2=π(3)2=9πsq cm
Then area of circle whose area is equal to sum of both circles=16π+9π=25π sq cm
let the radius of new circle is R cm
∴πR2=25π
⇒R2=25
⇒R=5 cm
So the radius of new circle =5 cm
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