find the radius of a circle whose area is equal to the difference of the area of two circle of radii 6cm and 10 cm respectively
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Answered by
2
Answer:
Let the radius of the first circle be r1
and second circle be r2.
third circle be R.
Given,
r1=8cm.r2=6cm.
A/q.
phi R^2=phi r1^2+phi r2^2.
phi R^2=phi(8^2+6^2).
R^2=64+36
R^2=100
R=10.
therefore the radius of the third circle of 10.CM.
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Answered by
1
Answer:
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Step-by-step explanation:
Find the radius of a circle whose area is equal to the difference of the areas of two circles of radii 6 cm and 10 cm respectively
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