Question

Find the radius of a circle whose area is equal to the difference of the areas of two circles of radii 6 cm and 10 cm respectively​

Answer 1

Answer:

Let the radius of the first circle be r1

and second circle be r2.

third circle be R.

Given,

r1=8cm.r2=6cm.

A/q.

phi R^2=phi r1^2+phi r2^2.

phi R^2=phi(8^2+6^2).

R^2=64+36

R^2=100

R=10.

therefore the radius of the third circle of 10.CM.

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Step-by-step explanation: